[ECP 1026]Reverse number breakdown

// Feel free to optimize or correct the code at the Facebook page, your name will be added to the code ;)
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//Revised code

#include <stdio.h>

int main()
{
    int num;
        int rev_num = 0;
        int perm;
        int remainder;

    printf("Enter a 6-digit integer:");
    scanf("%d", &num);
    printf("\n");
    perm = num; //Store original number in a permanent variable

    if(num > 100000){

        if(num < 1000000) {
        //6 Digit check

    //reverse program start

    while(num > 0)
    {
        rev_num = rev_num*10 + num%10; //add zero to the last digit such 10 becomes 100
                                        //This way we can add the last digit, 100 + 3 = 103
                                        //The last digit is obtained by getting the remainder of the number such as
        printf("%d\n", rev_num); //reversed number stored in Rev_num
        num = num/10;
    }
    //reverse program end

    printf("The reversed is %d\n", rev_num);

    //digit seperator start
    printf("The reversed digit intergers are ");
    while(perm)
        {
        remainder = perm % 10;
        perm = perm / 10;
        printf("%d ", remainder);
        }
        //digit seperator end
        }

        else{
        printf("Sorry, only 6-digit integers are accepted.");
        }
        }
        else{
        printf("Sorry, only 6-digit integers are accepted.");
        }
        return 0;
}